1.

The wave length of a beam of light is 25.0m m. Its wave number is

Answer»

`4.0xx10^(1)m^(-1)`
`4.0xx10^(6)CM^(-1)`
`4.0xx10^(6)m^(-1)`
`25.0xx10^(4)cm^(-1)`

Solution :`barv=1/(lamda)=1/(25xx10^(-6))=4.0xx10^(4)m^(-1)`
`=4.0xx10^(2)cm^(-1)`


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