Related InterviewSolutions

• What is the normality of `0.3 M H_(3)PO_(4)` when it undergoes the reaction as ? `H_(3)PO_(4) + 2OH^(-) to HPO_(3)^(2-) + 2H_(2)O`A. 0.3 NB. 0.15 NC. 0.60 ND. 0.90 N
• 150 mL of `N//10` HCl is required to react completely with 1.0 g of a sample of limestone. Calculate the percentage purity of calcium carbonate.
• 20 mL of a solution containing 0.2 g of impure sample of `H_(2)O_(2)` reacts with 0.316 g of `KMnO_(4)` (acidic). Calculate : (a) Purity of `H_(2)O_(2)` (b) Volume of dry `O_(2)` evolved at `27^(@)C` and 750 mm pressure.
• Which of the following acids is added in the titration of oxalic acid and potassium permanganate ?A. `HNO_(3)`B. HClC. `CH_(3)COOH`D. `H_(2)SO_(4)`
• 1.2 g of a sample of `CaOCl_(2)` were suspended in water made up to 100 mL. 25 mL of this solution was treated with KI and the `I_(2)` liberated corresponded to 10 mL of `N//25` hypo. Calculate the percentage of `Cl_(2)` available in `CaOCl_(2)`.
• 1.355 g of pyrolusite sample are added to 50 mL of 1 N oxalic acid solution containing sulphuric acid. After the reaction is completed, the contents are transferred to a measuring flask and the volume made up to 200 mL. 20 mL of this solution is titrated against `KMnO_(4)` solution whose strength is `2 g//L` and 31.6 mL of `KMnO_(4)` solution are required. Calculate the percentage purity in the given sample of pyrolusite.
• 1.6 g of pyrolusite was treated with 60 mL of normal oxalic acid and some `H_(2)SO_(4)`. The oxalic acid left undecomposed was made up to 250 mL, 25 mL of this solution required 32 mL of 0.1 N potassium permangante `(KMnO_(4))`. Calcualte the percentage of pure `MnO_(2)` in pyrolusite.
• How many mL of a 0.05 M `KMnO_(4)` solution are required to oxidise 2.0 g of `FeSO_(4)` in a dilute solution (acidic) ?
• Equivalent mass of a substance may be calculated as, Equivalent mass`=("Molecular mass")/("n-factor")=("Atomic mass")/(n-factor")` n-factor= Basicity of acid or acidity of base n-factor= Number of moles of electrons gainted or lost per mole of oxidising or reducing agents n-factor= Total positive or negative valency of a salt n-factor= Valency of an ion. Concept of n-factor is very important for redox as well as for non-redox reactions. `BrO_(3)^(-)` ion reacts with `Br^(-)` to form `Br_(2)`, in acid medium. The equivalent mass of `Br_(2)` in this reaction is :A. `(4 M.w.)/(6)`B. `(3M.w.)/(5)`C. `(5M.w.)/(3)`D. `(5M.w.)/(8)`
• Equivalent mass of a substance may be calculated as, Equivalent mass`=("Molecular mass")/("n-factor")=("Atomic mass")/(n-factor")` n-factor= Basicity of acid or acidity of base n-factor= Number of moles of electrons gainted or lost per mole of oxidising or reducing agents n-factor= Total positive or negative valency of a salt n-factor= Valency of an ion. Concept of n-factor is very important for redox as well as for non-redox reactions. When `KMnO_(4)` is titrated against ferrous ammonium sulphate in acid medium then equivalent mass of `KMnO_(4)` will be :A. `("Molecular mass")/(10)`B. `("molecular mass")/(5)`C. `("Molecular mass")/(3)`D. `("molecular mass")/(2)`