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The volume of the frustum of a cone is 1/3 πh[r12 + r22 - r1r2] where h is vertical height of the frustum and r1, r2 are the radii of the ends. |
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Answer» Solution: False Since, The volume of the frustum of a cone is 1/3 πh[r12 + r22 + r1r2] where h is vertical height of the frustum and r1, r2 are the radii of the ends. |
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