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The volume of oxygen at STP required to burn 2.4 g of carbon completely is :A. 1.12 LB. 8.96 LC. 2.24 LD. 4.48 L |
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Answer» Correct Answer - D `C+O_(2)toCO_(2)` `2.4/12=0.2` mole of carbon `:. 0.2" mole of need 0.2 mole of " O_(2)` So vol. of 0.2 mole `O_(2)" at " STP=0.2xx22.4=4.48 L` |
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