The volume of `H_(2)` gas at NTP obtained by passing 4 amperes through acidified `H_(2)O` for 30 minutes isA. 0.836LB. 0.0432LC. 0.1672LD. 5.6L

The volume of `H_(2)` gas at NTP obtained by passing 4 amperes through

1.	The volume of `H_(2)` gas at NTP obtained by passing 4 amperes through acidified `H_(2)O` for 30 minutes isA. 0.836LB. 0.0432LC. 0.1672LD. 5.6L
Answer» Correct Answer - A Quantity of electricity passed `=4Axx(30xx60s)=7200C` `2H_(2)O+2e^(-)rarrH_(2)+20H^(-)` `2xx96500C` liberate `H_(2)=22.4L` at STP 7200C will liberate `=(22.4)/(2xx96500)xx7200C` `=0.836L`

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The volume of `H_(2)` gas at NTP obtained by passing 4 amperes through acidified `H_(2)O` for 30 minutes isA. 0.836LB. 0.0432LC. 0.1672LD. 5.6L

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