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The volume of a right circular cylinder, 14 cm in height is equal to that of a cube whose edge is 11 cm. The radius of the base of the cylinder is (a) 5.2 cm (b) 5.5 cm (c) 11 cm (d) 22 cm |
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Answer» (b) 5.5 cm Let the radius of the base of the cylinder be r cm. Then, \(\frac{22}{7}\times{r}^2\times14=(11)^3\) ⇒ r2 = \(\frac{11\times11\times11\times7}{22\times14}\) = \(\frac{121}{4}\) ⇒ r = \(\sqrt{\frac{121}{4}}=\frac{11}{2}\) = 5.5 cm. |
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