The volume of a liquid flowing out per second of a pipe of length l an

1.	The volume of a liquid flowing out per second of a pipe of length l and radius r is given by V=\frac{\pi}{8} \frac{P_{\gamma}^{1}}{\eta l}
Answer» Volume per sec = L^3 T^-1Now according to above equationV= P r^4 / ( neta ) l =( M L^-1 T^-2 ) ( L^4 )-------------------------------( M L^-1 T^-1 ) ( L ) = L^3 T^-1 what happened to 180/8

The volume of a liquid flowing out per second of a pipe of length l and radius r is given by V=\frac{\pi}{8} \frac{P_{\gamma}^{1}}{\eta l}

Answer»

Volume per sec = L^3 T^-1Now according to above equationV= P r^4 / ( neta ) l

=( M L^-1 T^-2 ) ( L^4 )-------------------------------( M L^-1 T^-1 ) ( L )

= L^3 T^-1

what happened to 180/8