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The volume of 2.89 g of carbon monoxide at `27^(@)C` and 0.821 atm pressure isA. 2.5 LB. 4 LC. 3.5 LD. 3 L

Answer» Correct Answer - D
`n=(m)/(M)=(2.8)/(28)=0.1`
`V=(nRT)/(P)=(0.1xx0.0821xx300)/(0.821)=3L`


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