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The volume of `2.8 g` of carbon monoxide at `27^(@) C` and `0.821 atm` pressure `(R = 0.821 "atm" K^(-1) "mol"^(-1))`A. `0.3 L`B. `1.5 L`C. `3 L`D. `30 L` |
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Answer» Correct Answer - C According to the ideal gas equation , we have `pV = nRT` or `V = (nRT)/(p)` `n_(CO_(2)) = (m_(CO_(2)))/("Molar mass"_(CO_(2))) = (2.8 g)/(28 g "mol"^(-1)) = 0.1 "mol"` `:. V = ((0.1 "mol")(0.0821 (L "atm")/(K "mol")) (300 K))/((0.821 "atm"))` `= 32` |
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