The volume of 0.1M oxalic acid

1.	The volume of 0.1M oxalic acid
Answer» in an acidic medium 5H2C2O4 + 2KMnO4 + 3H2SO4 = K2SO4 +2MnSO4 + 10CO2 + 8H2O V x M = 0.02 x .025 = 0.0005 (KMnO4) By balanced equation 2 moles of KMnO4 REACTS with 5 moles of acid 1.25 x 10–3 MOL REACT completly 0.1 M x V = 1.25 x 10–3 mol V = 12.5 mL of acid hope helped !!!!

Answer»

in an acidic medium

5H2C2O4 + 2KMnO4 + 3H2SO4 = K2SO4 +2MnSO4 + 10CO2 + 8H2O

V x M = 0.02 x .025 = 0.0005 (KMnO4)

By balanced equation 2 moles of KMnO4 REACTS with 5 moles of acid

1.25 x 10–3 MOL REACT completly

0.1 M x V = 1.25 x 10–3 mol

V = 12.5 mL of acid

hope helped !!!!

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