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The volume occupied by 11.5 g of carbon dioxide at STP is approximately equal to: (A) 5.9 L (B) 22.5 L (C) 86 L (D) 259 L |
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Answer» Correct option is: (A) 5.9 L Molecular weight of \(CO_2\) = 44g/mol Number of moles\(CO_2\) = \(\frac {11.5}{44}mol\) = 0.26 mol Using ideal gas equation PV = nRT V = \(\frac {0.26\times 0.082\times 273}{1\, atm}\) V = 5.82 L Correct option is (A) 5.9 L |
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