1.

The volume (in mL) of 0.1 M AgNO_(3) required for complete precipitation of chloride ions present in 30 mL of 0.01 M solution of [Cr(H_(2)O)_(5)Cl]Cl_(2), as silver chloride is close to

Answer»


Solution :`[Cr(H_(2)O)_(5)Cl]Cl_(2)+2 AgNO_(3)rarr 2 AgCl+[Cr(H_(2)O)_(5)Cl](NO_(3))_(2)`
Number of ionizable `Cl^(-)` ions in the complex = 2 Millimoles of `Cl^(-)` ions = Molarity `xx` volume `xx 2 = 0.01 xx 30 xx 2 = 0.6`
Therefore, `Ag^(+)` required for complete precipitation of `Cl^(-)` ions = 0.6 millimoles
As Millimoles = Molarity `xx` V ml
0.6 = `0.1xxV`
V = 6 ml.


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