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The voltage and current in an a.c. circuit are given by `E = 300 sin (omega t + pi//2)` and `I = 5 sin omega t`. What is power factor of the circuit and power dissipated in each cycle ? |
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Answer» Here, `E = 300 sin (omega + pi // 2), I = 5 sin omega t` `:. E_(v) = (300)/(sqrt 2)` and `I_(v) = (5)/(sqrt 2) A, phi = pi//2` Power factor` = cos phi = cos pi // 2 =` zero Average power dissipated/cycle `= E_(v) I_(v) cos phi = (300)/(sqrt 2) xx (5)/(sqrt 2) cos 90^(@) = 0` |
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