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The vertex of a parabola is (2, 2) and the coordinats of its twoextremities of latus rectum are `(-2,0)`and (6, 0). Then find the equation of the parabola. |
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Answer» Correct Answer - `(x-2)^(2)=-8(y-2)` Focus is midpoint of the extremities of latus rectum. Thus, focus is (2,0). Distance between focus and vertex is a=2. Also, axis of the parabola is x=2 and parabola is concave downward as focus lies below the vertex. Therefore, using equation `(x-h)^(2)=-4a(y-k)`, required equation of parabola is `(x-2)^(2)=-8(y-2)` |
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