The velocity of the image of a moving object in situation shown in figure is (given velocity w.r.t ground)

The velocity of the image of a moving object in situation shown in fig

1.	The velocity of the image of a moving object in situation shown in figure is (given velocity w.r.t ground)
Answer» SOLUTION :We know for the perpendicular component `(vecV_(1//M))_(bot)=-(vecV_(o//M))_(bot)` `(V_(IG))_(bot)-(V_(MG))_(bot)=-[(V_(OG))_(bot)-(V_(MG))_(bot)]` `(V_(MG))_(bot)= ((V_(OG))_(bot)+(V_(IG))_(bot))/2 IMPLIES -30=(10+(V_(IG))_(bot))/2 implies` `(V_(IG))_(bot)=-70` THe parallel component of velocity of image is same as that of OBJECT w.r.t ground . It does not depend on the velocity of mirror. So `(V_(IG))_(II)=5m//s`