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The velocity of sound in air, in water and in a given solid is, `330 ms^(-1), 1350 ms^(-1)` and `1500 ms^(-1)`, respectively. If a vibrating tuning fork of frequency 150 Hz is placed in each of these media, then find the distance covered by the sound in air, water and solid, respectively, at the end of 50 vibrations. |
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Answer» Speed of sound in air `= 330 ms^(-1)`. Speed of sound in water `= 1350 ms^(-1)`. Speed of sound in solid `1500 ms^(-1)`. Frequency of turning fork, (n) = 150 Hz. i.e., it performs 150 vibrations in 1 second. `therefore` The time taken by the tuning fork to complete 50 vibrations `= 1/3 s`. The distance travelled by sound in three media in 1 second is 330 m, 1350 m, 1500 m. `therefore` The distance covered by sound in the three given media in 1/3 s is `330 xx 1/3 = 110 m` in air. `1350 xx 1/3 = 450 m` in water. `1500 xx 1/3 = 500 m` in solid. |
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