the velocity of a particle moving along x axis is given as v=x2-5x+4 find the magnitude of the acceleration of the particle when the velocity of the particle is zero

the velocity of a particle moving along x axis is given as v=x2-5x+4 f

1.	the velocity of a particle moving along x axis is given as v=x2-5x+4 find the magnitude of the acceleration of the particle when the velocity of the particle is zero
Answer» EXPLANATION GIVEN velocity v=x2−5x+4 Acceleration a≡dvdt ∴a=ddt(x2−5x+4) ⇒a=(2xdxdt−5dxdt) We ALSO know that dxdt≡v ⇒a=(2x−5)v at v=0 above equation becomes a=0

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the velocity of a particle moving along x axis is given as v=x2-5x+4 find the magnitude of the acceleration of the particle when the velocity of the particle is zero

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