1.

the velocity of a particle is given by v,= 5-t^2 the average accleration of a particle between 3 and 5 sec will be

Answer»

A = dv/dt = -2T so AVERAGE a = -2×3+ -2×4 + -2×5 / 3= -8 so the PARTICLE deaccelerated by 8m/s^2



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