The velocity of a particle change with time according to the relation v=xt+yt^(2)+z. Give the dimensions of x,y and z if v is in ms^(-1) and t is in s.

The velocity of a particle change with time according to the relation

1.	The velocity of a particle change with time according to the relation v=xt+yt^(2)+z. Give the dimensions of x,y and z if v is in ms^(-1) and t is in s.
Answer» SOLUTION :`vto LT^(-1)`, so `XT=[xT]=[LT^(-1)]`, Hence `x=[LT^(-2)]`. Similarly `yto[LT^(-3)]` and `zto[LT^(-1)]`