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The vectors `vecA` has a magnitude of 5 unit `vecB` has a magnitude of 6 unit and the cross product of `vecA and vecB` has a magnitude of 15 unit. Find the angle between `vecA and vecB`. |
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Answer» If the angle between `vecA and vecB is theta`, the cross product will have a magnitude `|vecAxxvecB|=AB sintheta` OR, `15=5XX6 sintheta` or, ` sin theta = 1/2` thus,` theta= 30^0 or 150^0`. |
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