1.

The vapour pressure of water at 20^(@)C is 17.5 mm Hg. If 18 g of glucose (C_(6)H_(12)O_(6))is added 178.2 g of water at 20^(@)C, the vapour pressure of the resulting solution will be :

Answer»

<P>17.325 MM Hg
17.675 mm Hg
15.750 mm Hg
16.500 mm Hg

Solution :ACCORDING to Raoult's Law.
`P_(A)=P_(A)^(@)X_(A)`
`X_(A)=n_(A)/(n_(A)+n_(B))=((178.2)/18)/((188.2)/18+18/180)`
`=(9.9)/(9.94)=0.99`
`P_(A)=(17.5mm)xx0.99=17.32 mm`


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