The values of the rate constant of a reaction weredetermined at severa

1.	The values of the rate constant of a reaction weredetermined at several temperatures. A plotlogk Vs 1/T gave a straight line with slope of -2.1x10 K. What is the activation energy of the?
Answer» ANSWER: According to Arrhenius equation logk=logA− 2.303 E a ⋅ T 1 Plot of LOG K vs T 1 is a straight line. Slope = − 2.303R E a Intercept = log A solution

The values of the rate constant of a reaction weredetermined at several temperatures. A plotlogk Vs 1/T gave a straight line with slope of -2.1x10 K. What is the activation energy of the?

Answer»

According to Arrhenius equation

logk=logA−

2.303

⋅

Plot of LOG K vs

is a straight line.

Slope = −

2.303R

Intercept = log A

solution