The value(s) of x, for which the 6th term in the expansion of [2log2� – InterviewSolution

1.	The value(s) of x, for which the 6th term in the expansion of [2log2√(9x−1+7)+12(1/5)log2(3x−1+1)]7 is 84, is equal to
Answer» The value(s) of $x,$ for which the $6^{t h}$ term in the expansion of ${[2^{{log}_{2} \sqrt{(9^{x - 1} + 7)}} + \frac{1}{2^{(1 / 5) {log}_{2} (3^{x - 1} + 1)}}]}^{7}$ is $84$ , is equal to

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