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The Value ot teh lso |
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Answer» Let tan(15°) = tan(45°-30°)We know that tan(A - B) = (tanA - tanB) /(1 + tan A tan B)⇒tan(45°-30°) = (tan45°- tan30°)/(1+tan45°tan30°)= {1- (1/√3)} / {1+(1/√3)}∴ tan15° = (√3 - 1) / (√3 + 1) |
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