The value of y in (y-5)^2=-16

1.	The value of y in (y-5)^2=-16
Answer» ANSWER: Step-by-step EXPLANATION: (y-5)^2=16 When we SOLVE the bracket, we will get y^2+(5)^2-2(y)(5)=16 y^2+25-10y=16 y^2-10y+25-16=0 y^2-10y+9=0 by discriminant method, D=b^2-4ac D=91 roots of the EQUATION are, 10+ $\sqrt{91$ /2 and 10- $\sqrt{91$ /2 so,value of y is 10+ $\sqrt{91$ /2or 10- $\sqrt{91$ /2

Answer»

ANSWER:

Step-by-step EXPLANATION:

(y-5)^2=16

When we SOLVE the bracket, we will get

y^2+(5)^2-2(y)(5)=16

y^2+25-10y=16

y^2-10y+25-16=0

y^2-10y+9=0

by discriminant method,

D=b^2-4ac

D=91

roots of the EQUATION are,

10+ $\sqrt{91$ /2 and 10- $\sqrt{91$ /2

so,value of y is 10+ $\sqrt{91$ /2or 10- $\sqrt{91$ /2

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The value of y in (y-5)^2=-16​

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The value of y in (y-5)^2=-16