1.

The value of 'X', when 3^ x = √3\9 is:​

Answer»

ANSWER:

{3}^{x} = \frac{ \sqrt{3} }{9}

{3}^{x} = \frac{3^{ \frac{1}{2} } }{ {3}^{2} }

{3}^{x} = {3}^{ \frac{1}{2} - 2 }

{3}^{x} = {3}^{ \frac{ - 3}{2} }

As BASES are same,

x = \frac{ - 3}{2}

So that's your answer


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