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The value of x such that 8x+4, 6x-2, 2x-7 will form an AP is |
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Answer» a = 8x + 4 b = 6x-2 c = 2x - 7 As a , b and c are in A.P then => b - a = c - b => b + b = c + a => 2b = c + a => 2 × ( 6x - 2 ) = ( 2x - 7 ) + ( 8x + 4 ) => 12x - 4 = 2x - 7 + 8x + 4 => 12x - 4 = 10x - 3 => 12x - 10x = -3 + 4 => 2x = 1 => x = 1 / 2 |
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