1.

The value of x such that 8x+4, 6x-2, 2x-7 will form an AP is ​

Answer»

a = 8x + 4

b = 6x-2

c = 2x - 7

As a , b and c are in A.P then

=> b - a = c - b

=> b + b = c + a

=> 2b = c + a

=> 2 × ( 6x - 2 ) = ( 2x - 7 ) + ( 8x + 4 )

=> 12x - 4 = 2x - 7 + 8x + 4

=> 12x - 4 = 10x - 3

=> 12x - 10x = -3 + 4

=> 2x = 1

=> x = 1 / 2



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