1.

The value of the limit limx→π24√2(sin3x+sinx)(2sin2xsin3x2+cos5x2)−(√2+√2cos2x+cos3x2) is

Answer» The value of the limit limxπ242(sin3x+sinx)(2sin2xsin3x2+cos5x2)(2+2cos2x+cos3x2) is


Discussion

No Comment Found

Related InterviewSolutions