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The value of the integral `int_(0)^(pi)(1-|sin 8x|)dx` is |
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Answer» Correct Answer - C `I=int_(0)^(pi)1-|sin 8x|dx` `= pi-int_(0)^(pi)(x|sin 8x|)dx` `= pi-int_(0)^(8.(8)/(pi))(x|sin 8x|)dx` `= pi-int_(0)^((8)/(pi))xsin 8xdx` `=pi-8 [(- cos 8x)/(8)]^((pi)/(8)) ` `P+(-1-phi)=pi-2` |
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