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The value of the expression [cosec (75° + θ) – sec (15° – θ) – tan (55° + θ) + cot (35° – θ)] is(A) – 1 (B) 0 (C) 1 (D) 3/ 2 |
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Answer» (B) 0 According to the question, We have to find the value of the equation, cosec(75°+θ) – sec(15°-θ) – tan(55°+θ) + cot(35°-θ) = cosec[90°-(15°-θ)] – sec(15°-θ) – tan(55°+θ) + cot[90°-(55°+θ)] Since, cosec (90°- θ) = sec θ And, cot(90°-θ) = tan θ We get, = sec(15°-θ) – sec(15°-θ) – tan(55°+θ) + tan(55°+θ) = 0 |
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