Saved Bookmarks
| 1. |
The value of θ (0 < θ < 2 π) satisfying cosec θ + 2 = 0 are(a) 210°, 330° (b) 210°, 240° (c) 220°, 330° (d) 240°, 300° |
|
Answer» Answer: (a) 210°, 330° Given, cosec θ + 2 = 0 ⇒ cosec θ = –2 ⇒ sin θ = − \(\frac{1}{2}\) = – sin 30° ⇒ sin θ = – sin 30° = sin (180° + 30°) or sin (360° – 30°) ⇒ sin θ = sin 210° or sin 330° ⇒ θ = 210°, 330°. |
|