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The value of tan−1(1√3)−sec−1(2√3) is equal to (a) 0 (b) π6 (c) π3 (d) π2 |
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Answer» The value of tan−1(1√3)−sec−1(2√3) is equal to (a) 0 (b) π6 (c) π3 (d) π2 |
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