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The value of `sum_(r=1)^(n) (-1)^(r+1)(""^(n)C_(r))/(r+1)` is equal toA. `-1/(n+1)`B. `-(1)/(n)`C. `(1)/(n+1)`D. `(n)/(n+1)` |
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Answer» Correct Answer - D `underset(r=1)overset(n)sum(-1)^(r+1)(.^(n)C_(r))/((r+1))= (1)/(n+1)underset(r=1)overset(n)sum(-1)^(r+1).^(n+1)C_(r+1)` `= 1/(n+1)(0-1+(n+1))= (n)/(n+1)` |
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