1.

The value of slope and intercept in the graph of Freundlich adsorption isotherm at 25^(@) C temperature are 0.5 and 0.4771 respectively.What will be the propertion of adsorption at 4 bar pressure?

Answer»

6
3
24
12

Solution :log `(X)/(m)`=log `k+(1)/(N)` log p
Here, log k=0.4771
`therefore` k=3
`(1)/(n)`=0.5
`therefore (x)/(m)=(3)(4)^(0.5)=3xx(4)^((1)/(2))`
`=3xxsqrt(4)=3xx2=6`


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