The value of sin2 θ + \(1\frac{1}{(1+tan^2θ)}\) is(1) sin2 θ(2)

1.	The value of sin2 θ + \(1\frac{1}{(1+tan^2θ)}\) is(1) sin2 θ(2) cos2 θ(3) Sec2 θ(4) 1
Answer» (4) 1 sin²θ + \(\frac{1}{1+tan^2\theta}\) = sin²θ + \(\frac{1}{sec^2\theta}\) = sin²θ + cos²θ = 1

The value of sin2 θ + \(1\frac{1}{(1+tan^2θ)}\) is(1) sin2 θ(2) cos2 θ(3) Sec2 θ(4) 1

Answer»

(4) 1

sin²θ + \(\frac{1}{1+tan^2\theta}\) = sin²θ + \(\frac{1}{sec^2\theta}\) = sin²θ + cos²θ = 1

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The value of sin2 θ + \(1\frac{1}{(1+tan^2θ)}\) is(1) sin2 θ(2) cos2 θ(3) Sec2 θ(4) 1

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