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The value of product6^1/2 x 6^1/4 ×6^1/8 ×6^1/16.....(a) 6(b) 36(C) 216 (d) 512(NOA - 2017) |
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Answer» Step-by-step explanation: 2 1
×6 2 1
×6 8 3
×6 4 1
×............... =6 2 1 + 4 2 + 8 3 + 16 4 +...................
=6 2 1 (1+ 2 2 + 2 2
3 + 2 3
4 +......................)
Let S=1+ 2 2 + 2 2
3 + 2 3
4 +............, then 2 S =S− 2 S
or, 2 S =1+ 2 1 + 2 2
1 + 2 3
1 +........... or, 2 S = 1− 2 1
1 ..... [or, 2 S = 1− 2 1
1 ..... [USING sum of infinite TERMS of an G.P] or, S=4 Then we have, 6 2 1
×6 2 1
×6 8 3
×6 4 1
×............... =6 2 1 ×4 =6 2 =36 |
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