1.

The value of p(t)=2+t+2tsq-tcb when t=0 is​

Answer»

ANSWER:

when t=0 then p(t) = 2

Step-by-step explanation:

p(t)=2+t+2tsq-tcb

p(0)=2+0+2(0)SQ-(0)cb

=2+0+0+0

=2

hope it HELPS....



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