The value of P (-1) when p(x) is x cube - 3 x square +5 is

1.	The value of P (-1) when p(x) is x cube - 3 x square +5 is
Answer» ong>Answer:P> p(X)=x^3-3x^2+5 to find p(-1) p(-1)=(-1)^3-3×(-1)^2+5 we KNOW that -1 raised to any ODD numbers is -1 itself and same raised to any even number is 1. therefore, it becomes p(-1)=(-1)-[3×(1)]+5 = -1-3+5 = -4+5 = 1 p(-1)=1.. hence solved.

Answer»

ong>Answer:P>

p(X)=x^3-3x^2+5

to find p(-1)

p(-1)=(-1)^3-3×(-1)^2+5

we KNOW that -1 raised to any ODD numbers is -1 itself and same raised to any even number is 1.

therefore, it becomes

p(-1)=(-1)-[3×(1)]+5

= -1-3+5

= -4+5

= 1

p(-1)=1..

hence solved.

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The value of P (-1) when p(x) is x cube - 3 x square +5 is​

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The value of P (-1) when p(x) is x cube - 3 x square +5 is