1.

The value of n²+2n[1+2+3+......+(n-1)] is​

Answer»

Answer:

n²+2n[1+2+3+....+(N-1)]

=n²+2n[n-1(n-1+1)/2]

=n²+n[n-1(n)]

=n²+n[n²-n]

=n²+n³-n²

=n³

I hope this answer MAY HELP you DEAR



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