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The value of n is(a) 0(c) 1You may use dimensional analysis to solve the problem(b) -1(d) none of these |
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Answer» ∫ dx/√2ax-x2 = an sin-1 [x/a - 1]. LHS is dimensionless because both the numerator and the denominator have the dimensions of x. Therefore the RHS should also be dimensionless. On the RHS, sin-1 [x/a - 1] is dimensionless. So an has to be dimensionless, which is possible only when n=0, i.e. an = 1 when n=0. (Note that a has the dimensions of x as x/a is dimensionless as seen from the argument of sin-1 function. thank you but can you pls show the solved ans. |
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