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The value of `((log)_2 24)/((log)_(96)2)-((log)_2 192)/((log)_(12)2)`is3 (b) 0(c) 2 (d) 1 |
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Answer» `[log_2^24*log_2^96]-[log_2^192]*[log_2^12]` `[log_2^(2^2*3)]*[log_2^(2^5^3)]*[log_2^(2^6*3)]*[log_2^(2^2*3)]` `[log_2^(2^3)+log_2^3][log_2^(2^5)+log_2^3)]-[log_2^(2^6)+log_2^3]*[log_2(2^2)+log_2^3]` `[3+log_2^3][5+log_2^3]-[6+log_2^3][2+log_2^3]` `15+8log_2^3+(log_2^3)^2-12-8log_2^3-(log_2^3)^2` `=15-12` `=3` Option A is correct. |
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