1.

The value of limn→∞⎡⎢⎢⎣1√(2n−12)+1√(4n−22)+1√(6n−32)+...+1n⎤⎥⎥⎦ is equal to

Answer»

The value of limn
1(2n12)+1(4n22)+1(6n32)+...+1n
is equal to



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