1.

The value of k, for which one root of the quadratic equation kx2 -14x +8 =0 is six times the other.

Answer»

Answer:

Let a root be r. Then other root is 6r

Then, r+6r = - (-14)/K and r.6r = 8/k

Hence, 7r = 14/k i.e r = 2/k

So, 6.(2/k)^2 = 8/k

=> 24/(k^2) = 8/k

=> k = 3

Step-by-step explanation:

Putting k you get the roots as 4 and 2/3 which are the roots of the equation. ALSO, 4 is 6 TIMES that of 2/3



Discussion

No Comment Found

Related InterviewSolutions