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The value of k for which kx^2-4x+4=0 has real equation and equal root |
Answer» ☆SoluTion =》Answer:-k=1 Given =》▪︎ kx²-4x+4=0 To find=》value of k Explanation =》kx²-4x+4=0 On comparing to the GENERAL FORM ax² +bx+C=0a= k , b= -4 , c= 4
for REAL and equal roots D=0 ( D= b²-4ac)b²-4ac=0 (-4)²- 4× k×4=0 16- 16k=0 -16k=-16 k= -16/16 k=1 value of k is 1 |
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