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The value of `K_(c)` for the reaction, `2 HI (g) hArr H_(2)g + I_(2) (g) ` is `1xx10^(-4)` At a given time, the composition of reaction mixture is `[HI] = 2xx10^(-5) "mol" and [I_(2)]=1xx10^(-5) ` mol In which direction will the reaction proceed ? |
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Answer» Reaction quotient (Q) `= ([H_(2)][I_(2)])/([HI]^(2))=((10^(-5))(10^(-5)))/((2xx10^(-5))^(2))=(1)/(4) = 0.25 =2.5xx10^(-1)` As `Q gt K_(c)`, the reaction will proceed in the reverse direction. |
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