The value of gem stone is varies as the square of weight. The gem ston

1.	The value of gem stone is varies as the square of weight. The gem stone is fall down and broke into two pieces. The ratio between the weights of two pieces is 2 : 7. The loss occurred is Rs. 3080. Find the original price of gem stone.1. Rs. 50002. Rs. 80003. Rs. 89104. Rs. 60605. Rs. 7500
Answer» Correct Answer - Option 3 : Rs. 8910 GIVEN : The loss occurred is Rs. 3080 The ratio between the weights of two pieces is 2 : 7 CONCEPT : The cost of a piece of gem stone varies with the square of its weight. ⇒ Price = k × weight²......(k is any constant) ASSUMPTION : Let the weight of a piece of gem stone be (2a + 7a = 9a) CALCULATION : The initial value of diamond = 81ka² Let the original price of a diamond be Ra.M. ⇒ 81ka² = M Then, The new value of diamond becomes = k (4a² + 49a²) = 53ka² New value of diamond = (53 × M)/81 Then, ⇒ M - 53M/81 = 3080 ⇒ M = Rs. 8910 ∴ The original price of gem stone is Rs.8910.

The value of gem stone is varies as the square of weight. The gem stone is fall down and broke into two pieces. The ratio between the weights of two pieces is 2 : 7. The loss occurred is Rs. 3080. Find the original price of gem stone.1. Rs. 50002. Rs. 80003. Rs. 89104. Rs. 60605. Rs. 7500

Answer» Correct Answer - Option 3 : Rs. 8910

GIVEN :

The loss occurred is Rs. 3080

The ratio between the weights of two pieces is 2 : 7

CONCEPT :

The cost of a piece of gem stone varies with the square of its weight.

⇒ Price = k × weight²......(k is any constant)

ASSUMPTION :

Let the weight of a piece of gem stone be (2a + 7a = 9a)

CALCULATION :

The initial value of diamond = 81ka²

Let the original price of a diamond be Ra.M.

⇒ 81ka² = M

Then,

The new value of diamond becomes = k (4a² + 49a²) = 53ka²

New value of diamond = (53 × M)/81

Then,

⇒ M - 53M/81 = 3080

⇒ M = Rs. 8910

∴ The original price of gem stone is Rs.8910.

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