1.

The value of frictional force on block in the given diagram is (Takeg 10 m/s?) [NCERT Pg. 101] m 3 kgL(2) 5 N(4) 9 N5Nu= 0.3(1) 4 N(3) 6 N​

Answer»

2) 5NExplanation:SEE the force = 5N, mu = 0.3 and mass is 3kgN= MG here.FS= usB = 0.3x30= 9.0.Which is greater than the force.But as we know static friction is self adjustable, the friction would limit itself to 5N only as it only NEEDS to resist a force of 5Nhope it HELP U



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