The value of equilibrium cons†an t for reaction is 16, HgO(s) = Hg( – InterviewSolution

1.	The value of equilibrium cons†an t for reaction is 16, HgO(s) = Hg(g) + 1/2O2(g) . The partial pressure of oxygen gas will be
Answer» The value of equilibrium cons†an t for reaction is 16, HgO(s) = Hg(g) + 1/2O2(g) . The partial pressure of oxygen gas will be

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