The value of determinant Δ=∣∣∣∣x2+42x1−x5x+12x1x+2x2∣∣∣∣,(x≠0) is equal to

The value of determinant Δ=∣∣∣∣x2+42x1−x5x+12x1x+2x2∣∣�

1.	The value of determinant Δ=∣∣∣∣x2+42x1−x5x+12x1x+2x2∣∣∣∣,(x≠0) is equal to
Answer» The value of determinant $Δ = ∣ ∣∣ ∣ \begin{matrix} x^{2} + 4 & 2 x & 1 - x 5 x + 1 & 2 x & 1 x + 2 & x & 2 \end{matrix} ∣ ∣∣ ∣, (x \neq 0)$ is equal to