1.

The value of cos² x + cos² y – 2cos x × cos y × cos (x + y) is

Answer»

Cos²x+cos²y-2cosx.cosy.COS(x+y)

cos²x+1-sin²y-2cosx.cosy.cos(x+y)

1+cos²x-sin²y-2cosx.cosy.cos(x+y)

1+cos(x+y).cos(x-y)-2cosx.cosy.cos(x+y)

1+cos(x+y){ cos(x-y)-2cosx.cosy }

1+cos(x+y){ cosx.cosy-sinx.siny-2cosx.cosy }

1+cos(x+y){ -cosx.cosy + sinx.siny }

1-cos(x+y){ cosx.cosy-sinxsiny }

1-cos(x+y).cos(x+y)

1-cos²(x+y)

sin²(x+y).



Discussion

No Comment Found

Related InterviewSolutions